Quartic Equation With 4 Real Roots3X4 + 6X3 – 123X2 – 126X + 1,080 = 0Quartic equations are solved in several steps. First, we simplify the equation by dividing all terms by ‘a’, so the equation then becomes:
X4 + 2X 3 – 41X2 – 42X + 360 = 0Where a = 1 b = 2 c = -41 d = -42 and e = 360Next we define the variable ‘f’:
f = c – (3b2/8)“Plugging in” the numbers from the above equation, we get:
f = -41 – (3*2*2/8)f = -42.5Next we define ‘g’:
g = d + (b3 / 8) – (b*c/2)“Plugging in” the numbers:
g = -42 + (8/8) – (2 * -41 / 2)g = 0Next, we define ‘h’:
h = e – (3*b4/256) + (b 2 * c/16) – ( b*d/4)Plugging in the numbers:
h = 370.5625Next, we “plug” the numbers ‘f’, ‘g’ and ‘h’ into the following cubic equation:
Y3 + (f/2)*Y2 + ((f2 -4*h)/16)*Y -g2/64 = 0Y3 -21.25*Y2 + (1,806.25 -4 * 370.5625 )/16*Y -02/64 = 0Y3 -21.25*Y2 + (1,806.25 -1,482.25)/16*Y -02/64 = 0Y3 -21.25*Y2 + 20.25*Y -0 = 0Next, we solve this cubic equation by using the method located at
solving cubic equations OR (much easier) using the
CUBIC EQUATION CALCULATOR.And the 3 roots of the equation are:
Y1= 20.25 Y2= 0 Y3= 1Let ‘p’ and ‘q’ be the square roots of ANY 2
non-zero roots (Y
1 Y
2 or Y
3).
p=SqRoot(20.25) = 4.5q=SqRoot(1) = 1r= -g/(8*pq) = 0s= b/(4*a) = 6/(4*3) = 0.5Then the four roots of the quartic equation are:
X1= p + q + r -s = 4.5 + 1 + 0 – .5 = 5
X2= p – q – r -s = 4.5 – 1 – 0 – .5 = 3
X3= -p + q – r -s = -4.5 + 1 – 0 – .5 = -4
X4= -p – q + r -s = -4.5 – 1 + 0 – .5 = -6